RESTful Web Services (JAX-RS) @QueryParam Example

This post is in continuation with web service tutorial (Part -9).

In previous post, we have used @PathParam for passing parameter to URL in RESTful Web Services json example and we have directly passed parameter values but JAXRS @QueryParam can be used to pass query parameters. In case of @QueryParam, we pass parameters as well as its values.
For example: http://localhost:8080/JAXRSJsonExample/rest/countries/country?id=3&countryName=Nepal
Here Parameter names are id,countryName and its values are 3,Nepal respectively.

@QueryParam can be used in case of filtering . When you want show both param as well value in url.
For example: Lets say you are showing list of customers on a website and you can show 10 at a time. When user click next , he will see next 10 customers, so in this case, we can [email protected] may look something like this


Here are steps to create a JAXRS json example which will use @QueryParam.

1) Follow steps on RESTful Web Services json example to create simple RESTful web services which [email protected]
2) Change to [email protected] as below.

That’s all. We need to run the application now.

Run the application

3) Right click on project -> run as -> run on server
Select apache tomcat and click on finish
4) Now pass country id and country name as parameter to url.

We are done with Restful web services json QueryParam example. If you are still facing any issue, please comment.

One Response

  1. Jitendra February 25, 2016

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